AngouriMath
Subset(AngouriMath.Entity,AngouriMath.Entity,System.Boolean)
Method (no overloads)
Summary
Whether every member of sub is a member of super ,
as a truth value, ornull where that is not settled. Both sets arrive
already simplified. The routes, in order: what the two shapes say outright, what the
set algebra says about a union, an intersection, a difference or a power set on either
side, the members of a finite set one by one, the chain the special sets sit on, the
ends of two intervals, the differencesub \ super where it evaluates, and last
the statementforall x in sub : x in super , which the quantifier decision
answers with the solver where the membership reads as a comparison.
https://github.com/asc-community/AngouriMath/issues/1409
as a truth value, or
already simplified. The routes, in order: what the two shapes say outright, what the
set algebra says about a union, an intersection, a difference or a power set on either
side, the members of a finite set one by one, the chain the special sets sit on, the
ends of two intervals, the difference
the statement
answers with the solver where the membership reads as a comparison.
https://github.com/asc-community/AngouriMath/issues/1409
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