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Integrate

 Method with 2 overloads

• Integrate​(System.​String,​AngouriMath.​Entity.​Variable,​AngouriMath.​Entity,​AngouriMath.​Entity)

  Summary

  Integrates definitely the given expression over the `x` variable, if can.
  May return an unresolved Integralf node.
  

  Parameter "str"

  The expression to be parsed and integrated
  

  Parameter "x"

  Over which variable to integrate

  Parameter "from"

  The lower bound for integrating

  Parameter "to"

  The upper bound for integrating

  Returns

  An integrated expression. It might remain the same or be transformed into nodes with no integrals.
  

  Example

  The bounds are substituted into the antiderivative and the difference is left
  standing, so the number wanted usually takes one more step:
  

  Console.WriteLine("sin(x)".Integrate("x", 0, "pi"));
  Console.WriteLine("sin(x)".Integrate("x", 0, "pi").Simplify());

  
  Prints
  

  -cos(pi) - -cos(0)
  2

• Integrate​(System.​String,​AngouriMath.​Entity.​Variable)

  Summary

  Integrates indefinitely the given expression over the `x` variable, if can.
  May return an unresolved Integralf node.
  

  Parameter "str"

  The expression to be parsed and integrated
  

  Parameter "x"

  Over which variable to integrate

  Returns

  An integrated expression. It might remain the same or be transformed into nodes with no integrals.
  

  Example

  The constant of integration is carried as the variable C; an integral with no
  antiderivative written in the library's functions comes back as the node itself,
  which is how this says it could not settle the question:
  

  Console.WriteLine("1 / x".Integrate("x"));
  Console.WriteLine("e ^ (x ^ 2)".Integrate("x"));
  Console.WriteLine("x ^ x".Integrate("x"));

  
  Prints
  

  ln(x) + C
  sqrt(pi) / 2 * erfi(x) + C
  integral(x ^ x, x)