AngouriMath
IntegrateOverAPowerOfALinearBesideABlock(AngouriMath.Entity,AngouriMath.Entity,AngouriMath.Entity.Variable,System.Boolean)
Method (no overloads)
Summary
split there as IntegrateOverAPowerOfXBesideABlock(AngouriMath.Entity,AngouriMath.Entity,AngouriMath.Entity.Variable,System.Boolean) splits at 0. With
Remarks
linear beside a binomial, which nothing took apart, since the split over written
factors takes linear and quadratic blocks only. The coefficients of N and B at the
root are read by Taylor's formula, and the block is left as it is written, for the
rules that read it. Rubi's 1.3.1.
https://github.com/asc-community/AngouriMath/issues/718
computed, every denominator is a written power of the block's bases at it, and the rest
is summed over one of them, written in powers of the base, and integrated in named
coefficients: with the root carried as
of thousands of nodes, and is 11,068 in half a second now. Rubi's 1.3.1:568 and 569.
https://github.com/asc-community/AngouriMath/issues/233
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