AngouriMath
MaximumRecurrenceDepth
Field
Summary
The most negative whole power
SolveANegativePowerOfALinearBesideAPowerOfAnotherByTheRecurrence(AngouriMath.Entity,AngouriMath.Entity.Variable,System.Boolean) takes down
the recurrence: each step is one term more in the answer. Sixteen, since Rubi's
1/(x^4 (b x^(2/3) + a x)^(3/2)) is 3/(u^13 (b + a u)^(3/2)) under u = x^(1/3) , and
past the bound it ran past the budget in the cancellation with functions as indeterminates.
SolveANegativePowerOfALinearBesideAPowerOfAnotherByTheRecurrence(AngouriMath.Entity,AngouriMath.Entity.Variable,System.Boolean) takes down
the recurrence: each step is one term more in the answer. Sixteen, since Rubi's
past the bound it ran past the budget in the cancellation with functions as indeterminates.
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