AngouriMath
SolveAFunctionOfTheReciprocalOfALinear(AngouriMath.Entity,AngouriMath.Entity.Variable,System.Boolean)
Method (no overloads)
Summary
Sines, cosines and the rest of a function of the reciprocal of a linear, beside a whole
power of the linear:L^m f(a + b/L^k) with L = c + d x . Under u = 1/L ,
dx = -du/(d u^2) , and it is -(1/d) u^(-m - 2) f(a + b u^k) : a polynomial times
the function form <= -2 , which by parts is elementary for a sine or cosine of a
linear.sin(a + b/x)/x^3 is -u sin(a + b u) . Rubi's 4.1.12 and 4.2.12,
(e x)^m (a + b sin(c + d x^n))^p for a negative n ; the exponential's case is
SolveAGaussianInAReciprocal(AngouriMath.Entity,AngouriMath.Entity.Variable).
https://github.com/asc-community/AngouriMath/issues/718
power of the linear:
the function for
linear.
SolveAGaussianInAReciprocal(AngouriMath.Entity,AngouriMath.Entity.Variable).
https://github.com/asc-community/AngouriMath/issues/718
Remarks
Every factor with the variable in it is read: a trigonometric function of something of
L with 1/L in it, or a whole power of L ; anything else and the rule
declines, rather than write a polynomial ofx in u . Only for m <= -3 :
the other powers are answered as written, and asked here would come back respelled.
declines, rather than write a polynomial of
the other powers are answered as written, and asked here would come back respelled.
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