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AngouriMath

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SolveALinearAndAQuadraticToOnePowerAsOneBinomial​(AngouriMath.​Entity,​AngouriMath.​Entity.​Variable,​System.​Boolean)

 Method (no overloads)

Summary

A linear and a quadratic to one power that is not whole, as one binomial:
integral g L^p Q^p = (L^p Q^p/P^p) integral g P^p where P = L Q is
A + B x^3, as (1 + x) (1 - x + x^2) is 1 + x^3.

Remarks

L^p Q^p/P^p is constant wherever it is continuous, for the reason
SolveTwoLinearsToOnePowerAsOneQuadratic(AngouriMath.Entity,AngouriMath.Entity.Variable,System.Boolean) gives, and the rules for a power
of a binomial answer the rest. Rubi's 1.2.1.2 1/((1 + x)^(1/3) (1 - x + x^2)^(1/3)) and 1/((b e - c e x)^(1/3) (b^2 + b c x + c^2 x^2)^(1/3)) were declined.
https://github.com/asc-community/AngouriMath/issues/718

























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