AngouriMath
SolveANestedRootByItsClosedForm(AngouriMath.Entity,AngouriMath.Entity.Variable,System.Boolean)
Method (no overloads)
Summary
Four nested roots with a closed form, Rubi's 1.3.3: sqrt(a + b sqrt(c + d x^2)) with a^2 = b^2 c ; sqrt(c x^2 + d sqrt(a + b x^4))/sqrt(a + b x^4) with
c^2 = b d^2 ; 1/((a + b x^n) sqrt(c x^2 + d (a + b x^n)^(2/n))) ; and
sqrt(a x^2 + b x sqrt(c + d x^2))/(x sqrt(c + d x^2)) with a^2 = b^2 d and
b^2 c + a = 0 . And the second over a power of a linear, for numbers.
Remarks
second and third are the derivative of
integral in
the answer is differentiated back before it is returned. Rubi's 1.3.2 and the Welz and
Timofeev suites declined all of them.
https://github.com/asc-community/AngouriMath/issues/718
the factors are conjugates whose sum is
hyperbolic tangent and roots, and the two together real. For positive numbers
Welz's 47 and 48, declined before.
https://github.com/asc-community/AngouriMath/issues/233
Angouri © 2019-2023 · Project's repo · Site's repo · Octicons · Transparency · 4862 pages online