AngouriMath
SolveAPowerTimesAHalfOddPowerOfTheLogarithm(AngouriMath.Entity,AngouriMath.Entity.Variable)
Method (no overloads)
Summary
A power of x times a half-odd power of a logarithm, x^p F^n with F =
ln x or A + B ln(c x^r) and 2n odd, onto the Gaussian's moments.
Witht = sqrt(F) and F' = s/x , dx = 2 x t dt/s , and
x^(p + 1) e^(-(p + 1) F/s) is a constant, so the integral is that constant times
2/s times the integral of t^(2n + 1) e^((p + 1) t^2/s) : an even moment of
the Gaussian, which the table answers. Atp = -1 it is
F^(n + 1)/(s (n + 1)) . Rubi's 3.1.2, (d x)^m (a + b ln(c x^n))^p for a
half-oddp .
https://github.com/asc-community/AngouriMath/issues/1501
With
the Gaussian, which the table answers. At
half-odd
https://github.com/asc-community/AngouriMath/issues/1501
Remarks
The constant is written x^(p + 1) e^(-(p + 1) F/s) , as Rubi writes it, rather
than withln(c x^r) split into ln c + r ln x , which holds only where
c is positive. The logarithm to the right of a whole power of it is
SolveAPowerTimesAPowerOfTheLogarithm(AngouriMath.Entity,AngouriMath.Entity.Variable)'s.
than with
SolveAPowerTimesAPowerOfTheLogarithm(AngouriMath.Entity,AngouriMath.Entity.Variable)'s.
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