AngouriMath
SolveARationalFunctionBesideAHalfOddPowerOfAQuadraticSplitFirst(AngouriMath.Entity,AngouriMath.Entity.Variable,System.Boolean)
Method (no overloads)
Summary
A rational function with symbols in it beside a half-odd power of a quadratic,
R(x) Q^(k/2) , its polynomial part divided out and the rest split into partial
fractions over the factors below the bar as written, each term beside the power the
question of one factor: Rubi's(a + b x + c x^2)^(3/2)/((d + e x) (f + g x)^2) and
x^4/((a + b x + c x^2)^(3/2) (d - f x^2)) .
fractions over the factors below the bar as written, each term beside the power the
question of one factor: Rubi's
Remarks
The terms are x^i Q^(k/2) and x^i Q^(k/2)/F^j for a linear or a quadratic F, each
answered by the rules for one factor beside the root, where the whole was declined: the
rules for a rational function beside the root of a quadratic read one factor below the
bar. The split is checked at sampled points before it is used. Late, at the question
asked, and with a symbol, as SolveARationalFunctionBesideARootOfALinearSplitFirst(AngouriMath.Entity,AngouriMath.Entity.Variable,System.Boolean) is for the root of a linear.
https://github.com/asc-community/AngouriMath/issues/233
answered by the rules for one factor beside the root, where the whole was declined: the
rules for a rational function beside the root of a quadratic read one factor below the
bar. The split is checked at sampled points before it is used. Late, at the question
asked, and with a symbol, as SolveARationalFunctionBesideARootOfALinearSplitFirst(AngouriMath.Entity,AngouriMath.Entity.Variable,System.Boolean) is for the root of a linear.
https://github.com/asc-community/AngouriMath/issues/233
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