SolveAReciprocalOfAnInverseTrigonometricFunction​(AngouriMath.​Entity,​AngouriMath.​Entity.​Variable,​System.​Boolean)

SolveByInverseTrigonometricSubstitution(AngouriMath.Entity,AngouriMath.Entity.Variable,System.Boolean) where the inverse function is
below the bar, asked before the general substitution search: under the substitution the
integrand is the sine and cosine integrals' at once, and the search in front of it spent
five seconds on x/((c + a^2 c x^2)^2 arctan(a x)) finding nothing. Only that
question is asked in u, of SolveATrigonometricOfALinearOverAPowerOfALinear(AngouriMath.Entity,AngouriMath.Entity.Variable).
Where the substitution leaves anything else -- a quadratic it does not read as a
multiple of the radicand, (a^2 + a^2 tan(u)^2)^3 -- the whole search in
u runs past thirty seconds, on integrands the general substitution search
answers in under one.