AngouriMath
SolveASymbolicPowerOfATrigonometricFunctionAsTheDerivativeOfAProduct(AngouriMath.Entity,AngouriMath.Entity.Variable)
Method (no overloads)
Summary
sine, cosine, secant or cosecant of a linear
Remarks
The integrand is read as f^m times a polynomial in f with only the constant and
square terms,alpha + beta f^2 , which matches p0 + p2 f^2 above where
beta p0 = alpha p2 ; the answer is (alpha/p0) G/u' . Rubi's 4.1.4.1, 4.2.4.1 and 4.5.4.1
sec(c + d x)^m (m - (1 + m) sec(c + d x)^2) and the like were declined.
The power is one of the integrand's factors, and one under the bar isf^(-m) : only then is the
integrandf^m times the rest, and a power in one term of a sum, as in
-m sec^m + (1 + m) sec^2 , is not a factor of it.
https://github.com/asc-community/AngouriMath/issues/718
square terms,
The power is one of the integrand's factors, and one under the bar is
integrand
https://github.com/asc-community/AngouriMath/issues/718
Angouri © 2019-2023 · Project's repo · Site's repo · Octicons · Transparency · 4862 pages online