SolveAnAlgebraicFunctionOfTheReciprocalOfX​(AngouriMath.​Entity,​AngouriMath.​Entity.​Variable,​System.​Boolean)

x = 1/u is one to one on each side of zero, and d/dx F(1/x) = -F'(1/x)/x^2,
so the answer in u written back holds wherever the integrand is defined. Only where x
stands nowhere but below a bar, as b/x^k in two sums or more, each below the bar
itself, and some power of such a sum is not whole: a rational function of x is the
partial fractions', one sum beside a power of x is read by the binomial rules as it
stands, and with a sum above the bar the routes this pre-empts answer, where in u
sqrt(a + b u)/(u^2 (c + d u)^3) ran past the budget. SolveByWritingEachLinearOnce(AngouriMath.Entity,AngouriMath.Entity.Variable,System.Boolean) wrote the
root over its linears, and the partial fractions it reached ran past the budget. At the
question asked, before that rule.
https://github.com/asc-community/AngouriMath/issues/233