AngouriMath
SolveAnExponentialInTheReciprocalOfALinear(AngouriMath.Entity,AngouriMath.Entity.Variable,System.Boolean)
Method (no overloads)
Summary
The same substitution where the exponent is not a Gaussian in u = 1/L :
L^m F^(a + b/L) or L^m F^(a + b/L^3) is
-(1/d) u^(-m - 2) F^(a + b u) or F^(a + b u^3) , an exponential beside a
power, asked as a question inu and written back with u = 1/L .
power, asked as a question in
Remarks
Rubi's 2.3, F^(a + b/(c + d x)) (c + d x)^2 , F^(a + b/(c + d x))/(c + d x) and F^(a + b/(c + d x)^3)/(c + d x) , were declined: the substitution was made only
for a Gaussian, whose moments the table answers, and an exponential of a linear or a
cube inu beside a power of it is the exponential integral's, or a power of the
cube's argument underw = u^3 , which the integrator answers when asked in
u .
https://github.com/asc-community/AngouriMath/issues/718
for a Gaussian, whose moments the table answers, and an exponential of a linear or a
cube in
cube's argument under
https://github.com/asc-community/AngouriMath/issues/718
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