AngouriMath
SolveByCancellingInsideALogarithm(AngouriMath.Entity,AngouriMath.Entity.Variable,System.Boolean)
Method (no overloads)
Summary
A logarithm whose argument is a quotient in x that cancels with
the functions ofx in it taken for indeterminates, with the
argument cancelled. That is the spelling the parser gives an inverse hyperbolic
function of a hyperbolic one --atanh(tanh(u)) is
1/2 ln((1 + T)/(1 - T)) with T = (E - 1)/(E + 1) and E = e^(2u) ,
which as one quotient is2E(E + 1)/(2(E + 1)) , and is 1/2 ln(E) : an
atom whose derivative isu' , which every rule downstream reads, where the
nested quotient was read by none.acoth(tanh(u)) is 1/2 ln(-E) the
same way. Kept as the logarithm rather than unwrapped tou , since
ln(e^(2u)) is 2u only on a strip, and the logarithm is exact
everywhere -- the answer carries it as Rubi's carriesatanh(tanh(u)) .
Rubi's 7.3.7 and 7.4.1. Asked as a question of its own.
https://github.com/asc-community/AngouriMath/issues/718
the functions of
argument cancelled. That is the spelling the parser gives an inverse hyperbolic
function of a hyperbolic one --
which as one quotient is
atom whose derivative is
nested quotient was read by none.
same way. Kept as the logarithm rather than unwrapped to
everywhere -- the answer carries it as Rubi's carries
Rubi's 7.3.7 and 7.4.1. Asked as a question of its own.
https://github.com/asc-community/AngouriMath/issues/718
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