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SolveByDividingByAHighPowerOfARootBesideAnotherBinomialFirst​(AngouriMath.​Entity,​AngouriMath.​Entity.​Variable)

 Method (no overloads)

Summary

SolveByDividingByTheRoot(AngouriMath.Entity,AngouriMath.Entity.Variable) asked at the question asked before the polynomial
term, for a power below -1 of a cube root or a higher odd one of a binomial in x^n beside a power of x of x^(-n) or below and a whole power of a second binomial in
x^n below the bar: Rubi's 1/(x^9 (a + b x^3)^(4/3) (c + d x^3)).

Remarks

Asked where it stands, a level down from the polynomial term and the cancellation with
functions as indeterminates, its rational function in u = x/(a + b x^3)^(1/3) ran past
the budget there, where at the question asked it is answered in two seconds. Only this
shape, where the division answered nothing in time; with square roots, and with the
power of x above x^(-n), the integrand is answered as it was.
https://github.com/asc-community/AngouriMath/issues/233

























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