AngouriMath
SolveByFoldingAnExponentialOfALogarithm(AngouriMath.Entity,AngouriMath.Entity.Variable,System.Boolean)
Method (no overloads)
Summary
An exponential of a multiple of a logarithm is a power of the argument:
e^(k ln(q)) is q^k , since e^(k ln q) is the definition of the
principal power for every complexq other than zero. That is the spelling the
parser gives every inverse hyperbolic function --acoth(a x) is
1/2 ln((a x + 1)/(a x - 1)) -- so e^acoth(a x) x^3 arrives as
e^(1/2 ln((a x + 1)/(a x - 1))) x^3 , which no exponential rule reads, and is
x^3 sqrt((a x + 1)/(a x - 1)) , a root of a quotient of linears, which the
radical substitution answers. Rubi's 7.4.2. The simplifier folds the same shape
since #1430; the integrand is not simplified before the rules see it, so the fold
is a rule here, asked as a question of its own so the closed rules meet it at the top.
https://github.com/asc-community/AngouriMath/issues/718
principal power for every complex
parser gives every inverse hyperbolic function --
radical substitution answers. Rubi's 7.4.2. The simplifier folds the same shape
since #1430; the integrand is not simplified before the rules see it, so the fold
is a rule here, asked as a question of its own so the closed rules meet it at the top.
https://github.com/asc-community/AngouriMath/issues/718
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