AngouriMath
SolveByTakingAWholePowerOutOfAPowerOfAProduct(AngouriMath.Entity,AngouriMath.Entity.Variable,System.Boolean)
Method (no overloads)
Summary
A power that is not whole of a constant times a whole power of something of x,
(c S^k)^p for a whole k past 1, as K S^(k p) , with
K = c^q (c S^k)^r/S^(k r) for the whole part q of p and the rest
r : Rubi's 1.3.2 x^m (c (a + b x^2)^2)^(3/2) is K x^m (a + b x^2)^3 ,
a polynomial, and was declined.
a polynomial, and was declined.
Remarks
derivative is
for a factor below the bar, as the factor of
SolveByTakingAPowerOfXOutOfAFractionalPower(AngouriMath.Entity,AngouriMath.Entity.Variable,System.Boolean) does. A whole power of the
constant times the power distributes exactly, which is why only the rest of
in
something of x by arithmetic, since a power of a function is the rules' for that function,
which write its sign; and at the top only, where the answer is the caller's.
https://github.com/asc-community/AngouriMath/issues/718
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