AngouriMath

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SolveByTheExponentAsTheVariable​(AngouriMath.​Entity,​AngouriMath.​Entity.​Variable,​System.​Boolean)

 Method (no overloads)

Summary

An exponential of a polynomial beside the polynomial's derivative, with the rest a
function of the polynomial: G^P k P' f(P) is k G^u f(u) under u = P.
Rubi's 2.3, e^(a + b x + c x^2) (b + 2 c x) (a + b x + c x^2)^(n/2).
https://github.com/asc-community/AngouriMath/issues/1501

Remarks

SolveBySubstitution(AngouriMath.Entity,AngouriMath.Entity.Variable,System.Boolean) reads this u and does not reach it: for its
own search it writes an exponential of a sum as a product of exponentials, so that
e^(e^x) e^x is e^u du, and e^(a + b x + c x^2) is then
e^a e^(b x) e^(c x^2), with no P left in it to replace. Declining took
it 24 s. Only a polynomial of degree two or more, whose derivative is a factor of its
own: an exponential of a linear is the table's.

























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