AngouriMath
SolveByWritingALinearBelowTheBarOverTheRadicand(AngouriMath.Entity,AngouriMath.Entity.Variable,System.Boolean)
Method (no overloads)
Summary
A linear below the bar that divides the radicand of a half-odd power beside it, written
over that radicand: the quadratic isP = L M , so 1/L is M/P and
L^(-n) P^s is M^n P^(s - n) , exactly, for a whole n .
x/((d + e x) sqrt(d^2 - e^2 x^2)) is the polynomial x (d - e x) over
(d^2 - e^2 x^2)^(3/2) , which the rules for a polynomial beside a half-odd power
of a quadratic answer. Rubi's 1.2.1.4 writes most of its rows this way.
over that radicand: the quadratic is
of a quadratic answer. Rubi's 1.2.1.4 writes most of its rows this way.
Remarks
The rules in front read a linear beside the root as a pole to take apart, and a linear
that divides the radicand leaves nothing to take apart: its residue is the radicand's
value at its root, zero. Only below the bar, so the rewrite never makes the shape it
reads --M^n is written above -- and a whole power only, where the rewrite
needs no branch.
https://github.com/asc-community/AngouriMath/issues/718
that divides the radicand leaves nothing to take apart: its residue is the radicand's
value at its root, zero. Only below the bar, so the rewrite never makes the shape it
reads --
needs no branch.
https://github.com/asc-community/AngouriMath/issues/718
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