AngouriMath
SolveByWritingAnImaginarySumOfACosineAndASineOverTheCosine(AngouriMath.Entity,AngouriMath.Entity.Variable,System.Boolean)
Method (no overloads)
Summary
reciprocals beside it, written as
which the rules for that sum answer.
Remarks
Where the exponential SolveByWritingAnImaginarySumOfACosineAndASineAsAnExponential(AngouriMath.Entity,AngouriMath.Entity.Variable,System.Boolean) writes declines: an odd power of the secant beside it, `sec(y)^5/(a cos(y) + i a sin(y))^2`,
is a half-odd power of `1 + tan(y)^2` in the tangent, and that is `(1 - i t)^(5/2) (1 + i t)^(1/2)`
over the sum, which the rules for `a + i a tan` take. Rubi's 4.7.2.
https://github.com/asc-community/AngouriMath/issues/718
is a half-odd power of `1 + tan(y)^2` in the tangent, and that is `(1 - i t)^(5/2) (1 + i t)^(1/2)`
over the sum, which the rules for `a + i a tan` take. Rubi's 4.7.2.
https://github.com/asc-community/AngouriMath/issues/718
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