AngouriMath
WithSymbolicBiquadraticsSplit(AngouriMath.Entity,AngouriMath.Entity.Variable)
Method (no overloads)
Summary
in it whose discriminant
written as the two quadratics it is,
Remarks
The rules below read a written quadratic in x , and a symbolic quartic is nothing
they factor:x^2/((x^2 - a)(x^4 - 2a x^2 + a^2 - b^2)^2) , which the root of a linear
makes of Rubi'scot(x)^3 sqrt(a + b sec(x)) in the secant, ran past a minute, and
written over(x^2 - a - b)(x^2 - a + b) it is answered in a fifth of a second.
https://github.com/asc-community/AngouriMath/issues/718
they factor:
makes of Rubi's
written over
https://github.com/asc-community/AngouriMath/issues/718
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