AngouriMath
WithTheCandidatesPowerLeftInX(AngouriMath.Entity,AngouriMath.Entity,AngouriMath.Entity.Variable,AngouriMath.Entity.Variable)
Method (no overloads)
Summary
in
Remarks
What the two are made of, compared without evaluating, and then the ratio at three points,
every other symbol pinned, screen each power cheaply, and only one that passes is worked
out: over one bar, with a negative fractional power written as a quotient by the
positive one, which it is on every branch, and simplified. That is what puts the
derivative ofsqrt(1 - a x)/sqrt(1 + a x) , a sum of two quotients of roots, over
one bar, and takes what is left besideu^(-1) to -1/(2 a) . A constant that
keeps an x is no constant, and the candidate stays refused.
every other symbol pinned, screen each power cheaply, and only one that passes is worked
out: over one bar, with a negative fractional power written as a quotient by the
positive one, which it is on every branch, and simplified. That is what puts the
derivative of
one bar, and takes what is left beside
keeps an x is no constant, and the candidate stays refused.
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