AngouriMath
SolveAsIndeterminatePower(AngouriMath.Entity,AngouriMath.Entity.Variable,AngouriMath.Entity,AngouriMath.Core.ApproachFrom)
Method (no overloads)
Summary
The limit of f(x)^g(x) where the pair is indeterminate and the second remarkable
limit does not already cover it -- that is, 0^0 and oo^0 -- ornull where that is not the shape or the exponent settles nothing.
limit does not already cover it -- that is, 0^0 and oo^0 -- or
Remarks
The descent substitutes each part's own limit, so both of these arrive as 0^0, which
is NaN. Written over as e^(g * ln f), the same question is the limit of a product of
something vanishing with something diverging, which the rules below can take apart.
rewrite would only hand the descent a product it reads no better than the power: the
descent substitutes the parts' limits and does not apply l'Hopital's rule to a part.
Asking outright is what puts the whole machinery behind the exponent.
and 0^oo and oo^oo are not indeterminate at all.
is NaN. Written over as e^(g * ln f), the same question is the limit of a product of
something vanishing with something diverging, which the rules below can take apart.
rewrite would only hand the descent a product it reads no better than the power: the
descent substitutes the parts' limits and does not apply l'Hopital's rule to a part.
Asking outright is what puts the whole machinery behind the exponent.
and 0^oo and oo^oo are not indeterminate at all.
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