AngouriMath
StirlingExponent(AngouriMath.Entity,AngouriMath.Entity,AngouriMath.Entity.Variable,AngouriMath.Entity)
Method (no overloads)
Summary
replaced by Stirling's expansion, or
factorial or the expansion would not be sound here.
Remarks
dropped **vanishes** -- where the asymptotic for
is merely relative. That is why the expansion is written for the logarithm and
applied to this exponent rather than substituted for the factorial in the base.
exponent the rewrite sits under: the answer is
error of
exponent. Requiring
products, quotients and powers assumes the parts are positive on the approach, which
is the same assumption the simplifier's
makes; it is confined to logarithms that actually hold a diverging factorial, so it
is reached only by expressions that have no answer at all without it.
#754
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