AngouriMath
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WithStepsAtTheirLimits(AngouriMath.Entity,AngouriMath.Entity.Variable,AngouriMath.Entity,AngouriMath.Core.ApproachFrom)
Method (no overloads)
Summary
in as that number. Each takes only whole values, so where it has a limit it takes
that value on the whole of some interval on that side: the substitution is exact
there, and not an approximation. Without it,
the form 0^0 and answered 1 through
is 0 to a positive power, which is 0.
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