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limitMemo
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Summary
The limits already found inside the outermost approach, keyed by the whole question.
Remarks
The machinery re-enters itself with questions it has already answered: in
tanh(log(arcsin(x), x)) at 0 from the left, the limit of the exponent ln(x) / ln(arcsin(x))
was taken four times over, at a second or more each, and the whole took ten seconds.
of limits spent, a re-entry guard at its depth -- and asked again elsewhere the same
question may be answered. A NaN is not kept either: it can be an indeterminate form
read on the way down, which callers withhold and search past rather than an answer.
Created and dropped with the sign memo, so nothing survives a call.
tanh(log(arcsin(x), x)) at 0 from the left, the limit of the exponent ln(x) / ln(arcsin(x))
was taken four times over, at a second or more each, and the whole took ten seconds.
of limits spent, a re-entry guard at its depth -- and asked again elsewhere the same
question may be answered. A NaN is not kept either: it can be an indeterminate form
read on the way down, which callers withhold and search past rather than an answer.
Created and dropped with the sign memo, so nothing survives a call.
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