AngouriMath
StepPieces
Description
Summary
An expression with floors and ceilings of x in it, written over a bounded range as the piecewise it is
there: each floor and ceiling replaced by its value on each piece, the pieces' ends exact, and each end owned by
the piece whose value it has.floor(x^2) over [0, 2] is 0 on [0, 1) , 1 on
[1, sqrt(2)) , 2 on [sqrt(2), sqrt(3)) , 3 on [sqrt(3), 2) and 4 at 2.
https://github.com/asc-community/AngouriMath/issues/1807
there: each floor and ceiling replaced by its value on each piece, the pieces' ends exact, and each end owned by
the piece whose value it has.
https://github.com/asc-community/AngouriMath/issues/1807
Remarks
answer a partition rather than a list of the roots the solver happened to find is the proof that between two
consecutive ends
value there (see Over(AngouriMath.Entity,AngouriMath.Entity.Variable,AngouriMath.Numerics.Interval)) --
Taylor's theorem
settles, and the whole is declined:
sine:
argument, where
Members
HighestDerivative
FieldMostWholeNumbers
FieldParameterWindow
Field
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