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TrinomialRevision(AngouriMath.Entity,AngouriMath.Entity.Variable,AngouriMath.Entity)
Method (no overloads)
Summary
binomial(n, i) binomial(n - i, k - i) summed from zero to k or to n:
2^k binomial(n, k) (Prob 8.9.15). Choosing i of the n and then
k - i of the rest is choosing k and then which i of them came first,
binomial(n, i) binomial(n - i, k - i) = binomial(n, k) binomial(k, i), the
trinomial revision; what is left is the binomial theorem at 1 + 1. The terms past
k have a negative lower index and are zero, so the range may end at either.
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