AngouriMath
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WithAFactorOfTheOtherOut(AngouriMath.Entity,AngouriMath.Entity)
Method (no overloads)
Summary
every term of the sum holds that factor, as it is or to a whole power, so that the
pairing meets it:
Remarks
A term that held the factor only to a power was not read as holding it, so
(x (y + 1) + (y + 1)^2) / (y + 1)^4 was left as written while
(x (y + 1) + (y + 1)) / (y + 1)^2 cancelled. The quotient rule squares the
denominator at each derivative, so the Taylor expansion ofe^x / (1 + x^2) took
its derivatives over(x^2 + 1)^2 , ^4 , ^8 .
https://github.com/asc-community/AngouriMath/issues/2301
denominator at each derivative, so the Taylor expansion of
its derivatives over
https://github.com/asc-community/AngouriMath/issues/2301
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