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WithinArccotanRange(AngouriMath.Entity)

Method (no overloads)

Summary

Whether the argument lies in the range arccotan answers in, which is
(-pi/2, pi/2] without zero.

Remarks

This library's arccotan is arctan(1/x) extended by
arccotan(0) = pi/2, so its range is that half-open interval and **not** the
(0, pi) that many texts use — arccotan(-1) is -pi/4. Zero is
excluded because cotan has no value there, so the composition has none either
and rewriting it to x would invent one.
https://github.com/asc-community/AngouriMath/issues/887

AngouriMath

Table of contents

AngouriMath

WithinArccotanRange​(AngouriMath.​Entity)

WithinArccotanRange(AngouriMath.Entity)