AngouriMath
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AnInfinityTimesASign(AngouriMath.Entity,AngouriMath.Entity,AngouriMath.Entity,System.Boolean,AngouriMath.Entity.Variable,AngouriMath.Entity,AngouriMath.Core.ApproachFrom)
Method (no overloads)
Summary
The limit of an infinity that does not depend on x times, or over,
other : that infinity, with the sign of other on the
way in, wherever the sign does not change there; otherwisenull .
way in, wherever the sign does not change there; otherwise
Remarks
An infinity is not a coefficient. Taken as one, the descent put the other part's limit in
its place, and +oo * x at 0 from the right became +oo * 0, which folds to 0, while -oo / x
at +oo became -oo / +oo and was answered 0 as well. At every point on the way in, though,
+oo * x is +oo and -oo / x is -oo. This is how ln(0) / ln(x), the logarithm of 0 to the
base x, was answered 0 at 0 from the right, where it is +oo all the way in.
Only where the product or quotient of the two limits leaves the answer open: the
other part tends to 0, or, for a quotient, to an infinity. Elsewhere the descent
below already answers it.
its place, and +oo * x at 0 from the right became +oo * 0, which folds to 0, while -oo / x
at +oo became -oo / +oo and was answered 0 as well. At every point on the way in, though,
+oo * x is +oo and -oo / x is -oo. This is how ln(0) / ln(x), the logarithm of 0 to the
base x, was answered 0 at 0 from the right, where it is +oo all the way in.
Only where the product or quotient of the two limits leaves the answer open: the
other part tends to 0, or, for a quotient, to an infinity. Elsewhere the descent
below already answers it.
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