AngouriMath
LnOfEInteger(PeterO.Numbers.EInteger,PeterO.Numbers.EContext)
Method (no overloads)
Summary
ln(n) for a whole number, kept inside the context's exponent range by
writing n = head * 10^shift and answering ln(head) + shift * ln(10).
Without the split,ln(2 ^ 10000) -- a 3011-digit integer, past the
context's ceiling of 10^1000 -- answers +oo instead of 6931.47...
writing n = head * 10^shift and answering ln(head) + shift * ln(10).
Without the split,
context's ceiling of 10^1000 -- answers +oo instead of 6931.47...
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